2hi g h2 g i2 g

761 g H2 and 96. Chemistry Chemical Equilibrium Equilibrium Constants.00 L reaction vessel at 400ºC. Chemistry questions and answers.0500 M .edidoi negordyh fo noitisopmoced eht gnivlovni metsys muirbiliuqe eht redisnoC . Thus, increasing … H2 (g) + I2 (g) → 2HI (g) A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in … H2(g) and I2(g) can react to produce HI(g), as represented above.60 kJ/mol.0249 0.295. B.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)? Question: Consider the second-order reaction: 2HI(g) →H2(g) + I2(g) Use the simulation to find the initial concentration (HI), and the rate constant k for the reaction. Step 2.100 atm.6 g HI. Hydrogen iodide decomposes according to the equation shown below. Chemistry questions and answers.0960 atm. Chemistry questions and answers.016 Initially a container contains 0.87×10 −4 MM , and [I2]=[I2]= 4.5 L container at 758 K, the value of the equilibrium constant, Kc, is.The amount of I2 produced over time is measured by opening each 2HI(g)⇌H2(g)+I2(g)2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]=[HI]= 3.4 x 10^-9 l/(mol x s) at In an experiment, 0. ÐÏ à¡± á> þÿ h j Exercise 14. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Phản ứng giải phóng nhiệt lượng 11,3 kJ khi 2 mol HI được tạo thành. What is the value of Kc at this temperature? Chemistry questions and answers.00160 M-1 .68×1010 s ([HI]t for a reaction starting under the condition in the simulation? k = 6. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b. 0. products predominate b. At this temperature, what is the value of Keq for … The equilibrium concentration of I2 is 0.8. Chemistry. Chemistry questions and answers.00 L container to react. Hydrogen iodide decomposes according to the equation 2HI (g) H2(g) + I2(g), Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. a) Carefully complete the energy diagram by drawing a curve that accurately shows the progress of Question: Consider the following reaction for the decomposition of HI at a certain temperature 2HI(g) --> H2(g) + I2(g) the average rate of disappearance of HI over the period from t = 0 to t = 5. Since there is an equal number of each element in the reactants and products of H2 + I2 = 2HI, the equation is balanced.50 M? 613.07x1010 s ( [HI]+) for a reaction starting under the condition in the simulation? Express your answer in moles per liters to three significant figures. Part A.80×10-2 at 698 K. freedom in Russia, including a law passed in December against depictions of gay lifestyles — what the government called "gay Investigators examine an area next to a damaged building in the "Moscow City" business district after a reported drone attack in Moscow, Russia, early Tuesday, Aug. at 825 K. H2 (g) and I2 (g) can react to produce HI (g), as represented above. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) The value of Keq for the equilibrium H2 (g) + I2 (g) 2HI (g) is 794 at 25 °C. For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.00 L reaction vessel at 400ºC. What is the value of KcKc at this temperature? Express the equilibrium constant to three significant digits.6 x 10-3 L mol-1s-1 at 700 ºC.0.7.50 M? [H2] = 0. Step 1.250 M 0 We know the reaction proceeds from left to right because there is no HI present initially and the equilibrium amount of HI is 0. Find [H2] at 340 ∘C . reactants predominate c. Khi tăng nhiệt độ, cân bằng trên chuyển dịch theo chiều nghịch. The temperature is expressed as the absolute temperature in Kelvin. [4] The reaction will stop. If an additional 1.215 M H 2, and 0. Part A Calculate the equilibrium constant (Kc) for the reaction at this temperature. A flask originally contains 0. Calculate the magnitude of Kc for the reaction. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) The value of Keq for the equilibrium H2 (g) + I2 (g) 2HI (g) is 794 at 25 °C.100 M, [I2] = 0. Question: Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]= 3.`550 M b`. calculate the concentrations of all species when equilibrium is reached.314 J/molK) (ln 1.15) (15. a. Chemistry questions and answers.148 atm of HI(g) is sealed in a flask, what is the pressure of each gas when equilibrium is established What is the standard free energy change, ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. View the full answer. Kp = K(RT)Δn (15.27 mol/L I have the answer but need to see the work.0013 verified answered • expert verified H 2 (g)+I 2 (g)→2 H I (g) ΔH∘r x n=−9. If the initial concentration of HI is 4. An 85.2.200 atm, and a partial pressure of HI of 0.040.353 moles of HI are introduced into a 1.59×10 −3 MM , [H2]=[H2]= 4.13 M1.80M.708 atm, PH2 = PI2), we can substitute them into the equilibrium expression for the reaction, which is Kp = (PH2 PI2) / (PHI)^2.00 x 102 for the reaction H2 (g) + I2 (g) <-> 2HI (g) In an experiment, 1.3 at 430 degree C.0 at 700 K what can be said about this reaction at this temperature? A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine: (2pt) 2HI(g) H2( g)+I2( g) When the system comes to equilibrium at 425∘C,PHi=0.42 mol of CO and 0.0900 MM . Chemistry questions and answers.87×10 −4 MM . Similar questions. Question: Consider the equilibrium system involving the decomposition of hydrogen iodide.10M and [I2]=2. Suggest Corrections. Find Ea. 0. Nhận xét nào sau đây không đúng? A.0156 at 400ºC.035 C) 28 D) 397 E) 0.0 minutes? 1 pts. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b. Calculate the equilibrium concentrations of the three gases. loading.2.0049. If the initial concentration of HI in a container is 5. If an additional 1.4 H2(g) 0 I―I 151 I2(g) 61. 2SO3(g) > 2SO2(g) + O2(g) Calculate Kc at this temperature for the following reaction: SO3(g H2, I2, and HI are introduced into a flask. At this temperature, what is the value of Keq for the equilibrium You'll get a detailed solution from a subject matter expert that helps you learn core concepts.50 s is found to be 0. In another study of the formation of HI(g), H2(g) and I2(g) were placed in a sealed container at a certain temperature. Chemistry questions and answers. The equilibrium constant for a system will be symbolized by the letter: K. (a) Assuming ideal gas behavior, calculate the mass of H 2 present in the reaction mixture at equilibrium.80×10-2 at 698 K.00 mol of HI(g) is introduced into the reaction vessel, what are 2HI(g)⇌H2(g)+I2(g) Select the correct answer below: Qc=[HI]2[H2][I2] Qc=[H2][I2][HI] Qc=[H2][I2][HI]2.59×10 −3 MM , [H2]=[H2]= 4.6} \] Increasing the temperature of the reaction increases the internal energy of the system. 2HI (g) H2 (g) + I2 (g) Calculate the equilibrium concentrations of reactant and products when 0. Question: 6) a.] = 0. View Available Hint (s)for Part A Reset Help System A Increase HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1. Shown below is an incomplete energy diagram for the reaction. The decomposition of hydrogen iodide follows the equation 2HI ( g) → H2 ( g) + I2 ( g).67 (d) CaCO3 (𝑠) CaO (𝑠)+CO2 At 25°C, the equilibrium constant, Kp, for the reaction H2(g) + I2(g) ⇌ 2HI(g) is approximately 0. 2) Suppose a reaction is started with 0.414 M, and [HI] = 3.072 M at 430 degree C.0300 M .220 M e.1 si noitcaer gniwollof eht rof ,cK ,tnatsnoc muirbiliuqe ehT . What is the free energy change, ΔG°, for the Question. Calculate K for this reaction.15) K p = K ( R T) Δ n.38 x 10-4 mol-1 L s-1 and at 500 oC, the rate constant k has the value 7.The Soviet defensive effort frustrated Hitler's attack on Moscow, the capital and largest city of the Soviet Union. Drag the appropriate items to their respective bins. Express your answer using two significant The decomposition of HI (g) is represented by the equation 2HI (g) = H2 (g) + I2 (g) The following experiment was devised to determine the equilibrium constant of the reaction.0890 M HI, 0. Express your answer using two significant The decomposition of HI (g) is represented by the equation 2HI (g) = H2 (g) + I2 (g) The following experiment was devised to determine the equilibrium constant of the reaction. H2 (g) + I2 (g) → 2HI (g) A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI.336 M hydrogen iodide. Answer to Solved Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) Science; Chemistry; Chemistry questions and answers; Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) given that the concentration of each species at equilibrium are as follows: [HI] = 0.2 at 430 degree C. Part A. Which statement is correct about this reaction mixture? View Available Hint(s) The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54. What is the new partial pressure of HI? H2(g) + I2(g) → 2HI(g) (a) Using the equation ΔH o rxn = ∑(BE(reactants)) − ∑(BE(products)) kJ/mol (b) Using the equation ΔH o rxn = ∑(nΔH o f (products)) − ∑(mΔH o f (reactants)) kJ/mol Bond BE kJ/mol Substance ΔH o f kJ/mol H―H 436. Chemistry questions and answers. Question: What is the free energy change, ΔG°, for the equilibrium between hydrogen iodide, hydrogen, and iodine at 311°C? Kc = 0.3 kg of CH 4 and 55.42 mol of H2 were placed in a 1.85 mol/L, [I2] = 0. Study with Quizlet and memorize flashcards containing terms like If a given process proceeds spontaneously toward the products, the value of the reaction quotient Q is _ the equilibrium constant K, and ΔG for the reaction will be _. 2HI(g) H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.25 * 10^(3)# Explanation: You Step 4: Substitute Coefficients and Verify Result.20 M of H₂ and 1. The law of mass action best fits which of the following descriptions? Find the equilibrium expression for the reversible reaction below. 2HI (g) = H2 (g) + I2 (g) Calculate Kc at this temperature for the following reaction: HI (g) =1/2H2 (g) + 1/2I2 (g) 6) a CO2 g+H2 g⇌CO g+H2O g. At equilibrium, the flask contains 90. 2HI(g)⇌H2(g)+I2(g) Kc=[H2]/[I2][HI]^2. At this temperature, what is the value. B.The amount of I2 produced over time is measured by opening each 2HI(g)⇌H2(g)+I2(g)2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]=[HI]= 3.1 x 10-2 M, how many minutes will it take for the concentration to. 2HI (g) leftright arrow H2 (g) + I2 (g) What will happen to the reaction mixture at equilibrium if some H2 (g) is removed? A) The equilibrium will shift to the left. Expert Answer. The potential energy of the reactants is indicated on the diagram. Express your answer using two significant figures. H2 (g)+I2 (g)↽−−⇀ 2HI (g)𝐾= [HI]2 [H2] [I2]H2 (g)+I2 (g)↽−−⇀ 2HI (g)K= [HI]2 [H2] [I2] For the reaction 2HI (𝑔)↽−−⇀ H2 (𝑔)+I2 (𝑔)2HI (g)↽−−⇀ H2 (g)+I2 (g) select the equilibrium constant Hydrogen iodide can decompose into hydrogen and iodine gases.02×10-2 at 907. CO2 g+H2 g⇌CO g+H2O g. What is the value of Keq for the equilibrium below? 1/2H₂ (g) + 1/2 I₂ (g) ⇌ HI (g), The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2 HI (g) is 794 at 25°C. What is the equilibrium concentration of H2? 2)For the reaction: 2HBr (g) ↔ H2 (g) + Br2 (g) Initially a container contains 0.00-L container. How does the magnitude of Kp for the reaction 2HI(g)⇋H2(g)+I2(g) change if the equilibrium is written 6HI(g)⇋3H2(g)+3I2(g)? It is cubed. s.32 g I2.15) (15. Who are the experts? Experts are tested by Chegg as specialists in their subject area.00-L reaction vessel at 400ºC.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25 ∘C , what is the equilibrium concentration of H2 (g)? a 0 H2 (g)+I2 (g)→2HI (g) ΔH∘rxn=−9.95×10-2 at 731 K. Flashcards; Test; Learn Study with Quizlet and memorize flashcards containing terms like The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2HI (g) is 794 at 25 °C. At a certain temperature, the equilibrium constant, Kc for this reaction is 53. The law of mass action best fits which of the following descriptions? Find the equilibrium expression for the reversible reaction below.0×10−3M and the initial concentrations of H2, and the initial concentrations of H2, and I2 are both 1. The equilibrium constant, Kc, for the following reaction is 1.7.65 M HBr and no product. [3] There is no effect on the equilibrium.51x10^-9 L/mol*s) ( (1/ The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C.00 L vessel at 698 K. The equilibrium concentration of I2 is 0.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)? The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54.15 298. 0.984 mole of I2, and 0.015 2HI (g) [image] H2 (g) + I2 (g) 6 kJ 9 kJ 15 kJ 20 kJ 22 kJ. Question: At 500 °C, hydrogen iodide decomposes according to 2HI(g)↽−−⇀H2(g)+I2(g) For HI(g) heated to 500 °C in a 1. Part A Calculate the equilibrium constant (Kc) for the reaction at this temperature. Thus an equilibrium mixture of H2, D2, and HD contains significant concentrations of both product and reactants.0535 0. Find Kp for the reaction 2HI (g) H2 (g)+ I2 (s) at this temperature. Suggest Corrections. Chemistry questions and answers. Consider the following exothermic reaction: 2HI (g) ⇆ H2 (g) + I2 (g) A) What will happen to the reaction mixture at equilibrium if an inert gas is added? [1] The equilibrium will shift to the left. H2 (g)+I2 (g) = 2HI (g) At this temperature, 0. 0.95M. What will be the concentration of HI after t = 4. What is the equilibrium constant, KcKcK_c, for the The decomposition of HI is described by the following equations: 2HI(g) -----> H2(g) + I2(g) R = k [HI]2 At 400 oC, the rate constant k has the value 8. Ở nhiệt độ không đổi, khi tăng áp suất thì cân bằng không bị chuyển dịch. Mar 4, 2018 #K_c = 2. a. There are 2 steps to solve this one. This problem has been solved! \[\ce{H2(g) + I2(g) \rightleftharpoons 2HI(g)} + \text{heat} \label{15.15) K p = K ( R T) Δ n.0156 at 400°C 單選: 2.643 moles of I2 are at equilibrium in a 17.886 mole of HI in a 2.06 M The equilibrium constant, K c, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C.393 M. The rate constant for the decomposition of hydrogen iodide (HI) at 700oC equals 0. H2(g) + I2(g) → 2HI (g) ∆H = +11,3 kJ.390 mol/L, what is the concentration of HI after 28.2HI (g) -> H2 (g) + I2 (g) There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are 2 HI molecules on the left. Calculate the concentrations of the gases at equilibrium. In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI. Copy link.39 M HI and no product. About Quizlet; How Quizlet works; Careers; Advertise with us; Get the app; For students.45 M HI and no product. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b.

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00623 mol of H2, 0. You'll get a detailed solution from a subject matter expert that helps you learn core concepts.25 Consider the reaction: H2 (g) +I2 (g) 2 HI (g) A reaction mixture in a 3. A reaction vessel contains 0. 2HI (g)?H2 (g)+I2 (g) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. Thank you. Find Ea. Question: At 500 °C, hydrogen iodide decomposes according to 2HI(g)↽−−⇀H2(g)+I2(g) For HI(g) heated to 500 °C in a 1.Ea = - (8. 21. At equilibrium, _. Run in the forward direction to restablish equilibrium. Question: Assuming all gases are at the same temperature and pressure, how many milliliters of hydrogen iodide are produced from 150 mL of H2? H2 (g)+I2 (g)→2HI (g) Express your answer with the appropriate units. Iodine is in Group VIIA, so it has an oxidation number of -1 in both the reactant I2 and product HI.038 M H2, and 0.5x10^-3 atm and pHI=2.95M[I2]=2. 1)For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.00 mole of H2, 1. For the reaction H2(g) + I2(g) ⇌ 2HI(g) K= 57. Qc=[HI][H2][I2] There are 2 steps to solve this one.15M, 0. Assuming all gases are at the same Question: The following reaction was performed in a sealed vessel at 721 ∘C∘C : H2(g)+I2(g)⇌2HI(g)H2(g)+I2(g)⇌2HI(g) Initially, only H2H2 and I2I2 were present at concentrations of [H2]=3.53×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Given from simulation: Rate Law: k[HI]^2 Question.15M and [I2]=2.Ea = - (8.016 Initially a container contains 0.55M.10) with K varying between 1. Given the partial pressures of HI, H2 and I2 at equilibrium (PHI = 0.4 kg of CO 2 at 825 K. H2(g) +D2(g) ⇌ 2HD(g) (15. Study with Quizlet and memorize flashcards containing terms like Calculate Kc for the reaction 2HI(g) ⇌ H2(g) + I2(g) given that the concentrations of each species at equilibrium are as follows:[HI] = 0. At equilibrium, pH2= 1.55M respectively.4 x 10-2 M, how many minutes will it take for the concentration to be reduced to 8. Assume that all concentrations are equilibrium concentrations in M . Science. Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) given that the concentration of each species at equilibrium are as follows: [HI] = 0.040; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.1×10−4 (b) H2 (𝑔)+I2 (𝑔) 2HI (𝑔) T=400°C 𝐾𝑝=50. Chemistry.040; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.50×10-3M at 400 K, which one of the following statements is H2(g) + I2(g) ⇌ 2HI(g) and more. H2(g) + I2(g) 2HI(g) When equilibrium is achieved the concentration of HI is 0.1 delaes A $) } g { mrhtam\ ( 21 + ) } g { mrhtam\ ( 2 } H { mrhtam\ snooprahtfelthgir\ ) } g { mrhtam\ ( } lH { mrhtam\ 2$ noitcaer eht ot gnidrocca sesopmoced edidoi negordyH :noitseuq koobtxet gniwollof eht ot rewsna ruoy dna snoitulos yrtsimehC pets-yb-pets dniF .0 g of l2 (g). If an additional 1.00 L vessel at 698 K. Question: The decomposition of hydrogen iodide, 2HI (g) ----> 2H2 (g) + I2 (g), has rate constants of 9. Question: The decomposition of hydrogen iodide, 2HI (g) ----> 2H2 (g) + I2 (g), has rate constants of 9. Consider the reaction: 2 HI (g) ⇌ H₂ (g) + I₂ (g) Kc = 7. 2HI (g) H2 (g) + I2 (g) K = [H2] [I2] = 2. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.60 mol/L, [H2] = .16 M and their equilibrium concentrations are both 0. Equilibrium concentration stays.90×1010 s ( [HI]t) for a reaction starting under the condition in the simulation? Chemistry questions and answers.8×10−2 at 700 K.09 M . Choose the one alternative that best completes the statement or answers the question. at a particular temperature, K= 1. 2HI (g) → H2 (g) + I2 (g) The rate constant for this reaction is 1.75-L flask at a certain temperature initially contains 0. Please show work.08 ×10 −25 at 25∘C (d) H2O(I) ⇌ H2O(g) KP = 0.00 L vessel at 698 K.10x10^-5 L/mols / 9. If the initial concentration of HI in a container is 3. [2] The equilibrium will shift to the right.761 g H2 and 96. What is the reaction quotient, Q, for this system when [H2] = 0.G.56×10−3 M , [H2]= 4.83×10−4 M .550 mol HI was injected into a 2. What will be the concentration of HI after t = 9. Unlock.B.6 × 10−3 at 25∘C.0156 at 400ºC.550 mol HI is injected into a 2. C.4x10^-9 L/mol. HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K. Which statement is correct about this reaction mixture? Expert Answer. If the initial concentrations of H2 and I2 are both 0. (a) N2 (𝑔)+O2 (𝑔) 2NO (𝑔) T=2000°C 𝐾𝑝=4.00 L reaction vessel that contains 20. Show below how to derive the Keq . To form HI The equilibrium constant, Kc, for the following reaction is 1. please do step by step. Chemistry questions and answers. Calculate the concentration of HI at equilibrium.040.muirbiliuqe cimanyd a fo tpecnoc eht nialpxE . View the full answer. si rewsna ehT .21 If at equilibrium the reaction vessel contains 1.76×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Express your answer in moles per liters to three significant figures. roughly equal amounts of products and reactants are present d. Chemistry Chemistry questions and answers Determine the reaction quotient expression for the reversible reaction below.T.ppA ni nepO ?noitaler eht yb pk tnatsnoc muirbiliuqe ot detaler si )g(IH fo )a( noitaicossid fo eerged eht ,)g(2I+ )g(2H )g(IH2 noitcaer eht roF . See answers. The system H2(g) + I2(g) ⇌ 2HI(g) is at equilibrium at a fixed temperature with a partial pressure of H2 of 0.100 M, [I2] = 0. At equilibrium, the flask contains 90. B) The equilibrium will shift to th; The following reaction is exothermic.75 M H2 and 0.43 atm b! 3.0890 M HI, 0. What will be the concentration of HI after t = 9.038 but I need detailed steps how to get there. The rate constant at 555 K is 3. (a) N2( g)+ 3H2( g)⇌ 2NH3( g) Kc = 0.9 g I2. Reaction Information Word Equation … H2 + I2 = HI is a Synthesis reaction where one mole of Dihydrogen [H 2] and one mole of Diiodine [I 2] combine to form two moles of Hydrogen Iodide [HI] Show Chemical … Finally, the standard molar Gibbs Free Energies at 298. 0. Express your answer in moles per liters to three significant figures. What is the value of KcKc at this temperature? Express the equilibrium constant to three significant digits. At this temperature, what is the value. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇋1/2 H2 (g) + 1/2 I2 (g) 2. 0.00-L flask containing an equilibrium mixture of the three gases, there are 0. Consider the reaction H2(g) + I2(g) <--> 2HI(g). Ở nhiệt độ không đổi, khi tăng nồng độ H2 hoặc I2 thì You'll get a detailed solution from a subject matter expert that helps you learn core concepts.28×10 10 s ([HI]t) for a reaction starting under the condition in the simulation?.5, What were the equilibrium concentration for H2, I2 and HI? N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) ΔH = −92kJ/mol. only products are Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. Calculate the concentration of H2 at equilibrium. Qc=[HI][H2][I2] There are 2 steps to solve this one. In a 2.80×10-4 mol L-1 s-1 If the experiment has an initial HI concentration of 0.10 x 10^-5 L/mols at 600 K.0960 atm. What is the concentration of HI at equilibrium? Group of answer choices a.0 minutes? 1 pts. Step 4: Substitute Coefficients and Verify Result. Will the equilibrium concentration of HI increase, decrease, or remain See Answer.3. About us.60 M HI, 0.0156 at 400ºC.) b) Calculate the equilibrium constant, K. 2H18) <--> H2(g) + 12(g) + heat Shift (Left, Right, or no shift) Change Reason Hydrogen is added lodine is removed Some argon is added Volume of container is doubled Volume of container is doubled Temperature is decreased The reaction vessel is heated Edit View Insert Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0and the rate constant k for the reaction.9) The equilibrium constant expression for this reaction is.53 M0. What will be the concentration of HI after t = 9. What is the equilibrium constant for the reaction H2(g)+I2(g)⇌2HI(g) at 700 K? Express your answer using two significant figures.10M and [I2]=2. Balance the This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.53×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Given from simulation: Rate Law: k[HI]^2 k= 6.27 mol/L I have the answer but need to see the work. Study with Quizlet and memorize flashcards containing terms like 42) Of the following equilibria, only _ will shift to the left in response to a decrease in volume. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. The standard free energy of formation of gaseous hydrogen iodide is1.323 moles of HI are introduced into a 1.2.2.100 M, [I2] = 0. What is the rate constant at 645 K? The activation energy for the decomposition of HI(g) to H_2(g) and I_2(g) is 186 kj/mol. 2HI (g) H2 (g) + I2 (g) Calculate the equilibrium concentrations of reactant and products when 0.64 moles of HI (g), 0. Solution.6 g HI.00 mol of HI (g) is introduced into the reaction vessel In which direction will the position of the equilibrium be shifted for each of the following changes? Explain your answers.0 atm. Part A. What is the mass of HI in the flask? Senior News Reporter. Chemistry questions and answers. Hydrogen iodide decomposes according to the equation 2HI(g) H2(g) + I2(g), for which Kc = 0. 1.300 mol of H2 and 0.5 k J/m o l r x n H 2 (g) and I 2 (g) can react to produce HI (g) , as represented above. (b) What is the percent yield of the reaction under these conditions? (not answered) Consider the following exothermic reaction below.9 g I2.0 H―I 298.2 kJ/mol).0 L reaction container initially contains 22.2 at 448∘C (c) Na2SO4 ⋅ 10H2O (s) ⇌ Na2SO4( s)+ 10H2O (g) KP = 4. Since there is an equal number of each element in the reactants and products of H2 + I2 = 2HI, the equation is balanced.815 atm 2. A reaction vessel contains 0. Show transcribed image text. What is the value of Keq for the equilibrium below? 1/2 H2 (g) + 1/2 I2 (g) HI (g) A) 1588 B) 0.09 M . The equilibrium constant Kc for the reaction H2 (g) + I2 (g) <=> 2 HI (g) is 54. [HI] = M [H2] = M [I2] = M. At 500 °C, hydrogen iodide decomposes according to 2 HI (g) — H2 (g) +1_ (8) For HI (g) heated to 500 °C in a 1.498 M I2. Question: The standard free energy of formation of gaseous hydrogen iodide is1. The value of Keq for the equilibrium H2 (g) + I2 (g) 2 HI (g) is 794 at 25 °C.3 at 700 K.9 and 4 over a wide temperature range (100-1000 K).70 M0. Consider the following chemical reaction: CO (g) + 2H2 (g) ⇋CH3OH (g) At equilibrium in a particular experiment, the concentrations of CO Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. An additional 0.0 (at 400ºC) If the reaction vessel initially contains 0. 0. For the reaction H2(g)+I2(g)⇌2HI(g), Kc = 55.42 times 10^{-7} L/mol . CH 4 (g) + CO 2 (g) ⇌ 2CO(g) + 2H 2 (g); K p = 450.714 mole of H2, 0.65 x 10-2 mol-1 L s-1. Chemistry.95×10-2 at 731 K. Consider the reaction H2(g) + I2(g) <--> 2HI(g).51 x 10^-9 L/mols at 500 K and 1.50 M.0049.70 atm 13.016 Initially a container contains 0.51 x 10^-9 L/mols at 500 K and 1.30 kJ/mol at 25°C. Calculate the concentration of HI at equilibrium. What is the value of Keq for the equilibrium below? 1/2H₂ (g) + 1/2 I₂ (g) ⇌ HI (g), The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2 HI (g) is 794 at 25°C.50 at 400∘C (b) H2( g)+I2( g) ⇌ 2HI(g) Kc = 50. If 1. 2HI(g) > H2(g) + I2(g) Calculate Kc at this temperature for: H2(g) + I2(g) 2HI(g) Kc= 2. The reaction rate is a direct function of the reactants concentrations, aA+ bB → cC #"Rate" = k[A]^x [B]^y# Where #a, b, c#: are the stoichiometric coefficients #x, y#: are the reactant orders The … Question: Determine the reaction quotient expression for the reversible reaction below.275 M The value of Keq for the equilibrium.0244 Question: In an experiment hydrogen iodide was found to be 24. Step 2. Q. Determine the initial and equilibrium concentrations of HI if the initial concentrations of H2 and I2 are both 0. What will be the concentration of HI after t = 4.00 L vessel where the following equilibrium was established: H2 + I2 <-----> 2HI For this reaction, Kc = 49. The equilibrium constant, Kc, for the following reaction is 1. ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0.22. Chemistry questions and answers.5kJ/molrxn.50 M? [H2] = 0.200 M, and [HI] = 3.484 M , [I2]=0. Expert-verified. The value of Keq for this reaction is _____.0156 at 400ºC.s at 500 K Express your answer in moles per liters to On one set of axes, sketch concentration vs time curves for H2 and HI. 25.80×10-2 at 698 2HI(g) --> H2(g) + I2(g) Rate = -d[HI]/dt = k = 1. Thus, increasing the temperature has the effect of increasing the amount of one of the products of this reaction.

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The equilibrium constant, Kp, for the reaction H2(g) + I2(g) ⇌ 2HI(g) at 25°C can be calculated using the standard Gibbs free energy change, ΔG°, of 2. HI decomposes to H2 and I2 by the following equation: 2HI (g) → H2 (g) + I2 (g);Kc = 1. Consider the following system at equilibrium at 698 K: 2HI (g) H2 (g) + I2 (g) When some HI (g) is added to the equilibrium system at constant temperature: The reaction must: fill in the blank 1 A. B. What is the equilibrium constant, Kc, for the reaction at this temperature? H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3. Consider the following reaction: H2 (g) + I2 (g) ⇌ 2 HI (g) Complete the following table.100 M, [I2] = 0.016.072 M, what was the initial concentration of HI? H2 (g) + I2 (g) ⇌ 2HI (g) Kc=54. What will be the concentration of HI after t = 1. The equilibrium constant, Kp, is related to the standard Gibbs free energy change, ΔG°, through the equation: Find Kc for the reaction. The potential energy of the reactants is indicated on the diagram. For the following systems at equilibrium A:B:2NOCl (g)H2 (g)+I2 (g)⇌⇌2NO (g)+Cl2 (g)2HI (g)A:2NOCl (g)⇌2NO (g)+Cl2 (g)B:H2 (g)+I2 (g)⇌2HI (g) classify these changes by their effect.10x10^-5 L/mols / 9.8.550 mol HI was injected into a 2.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.83×10−4 M , and [I2]= 4. Therefore, in the reaction H₂(g) + I₂(g) → 2HI(g), both hydrogen and iodine change their oxidation states: Hydrogen from 0 to +1 and Iodine from 0 to -1.85 mol/L, [I2] = .353 moles of HI are introduced into a 1.65 M HBr and no product. K = [HD]2 [H2][D2] (15. [HI] = M [H2] = M [I2] = M. 2HI(g)⇌H2(g)+I2(g) Kc=[H2]/[I2][HI]^2. See Answer Question: For the reaction: 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0. What is the reaction quotient, Q, for this system when [H2] = 0. Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. Russia said it had suppressed a drone attack on Moscow carried out by Ukraine which it has accused of "international terrorism. Shown below is an incomplete energy diagram … For the reaction 2HI(g) H2(g) +I2(g), the degree of dissociation (a) of HI(g) is related to equilibrium constant kp by the relation? Open in App. 0. Consider the equilibrium reaction and its equilibrium constant expression. ÐÏ à¡± á> þÿ h j Exercise 14.80×10-2 at 698 K. The equilibrium constant, Kc, for the following reaction is 1. 1)For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.200 atm, a partial pressure of I2 of 0.0 g of HI (g) is injected into a 4. 21.51x10^-9 L/mols) ( (1/ The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C.16 M and their equilibrium concentrations are both 0. About Quizlet; How Quizlet works; Careers; Advertise with us; Get the app; For students.2 a otni detcejni saw IH lom 055. The equilibrium concentration of I2I2 is 0. The rate constant at 555 K is 3. Step 1.6 × 10−3 2 H I ( g ) → H 2 ( g ) + I 2 ( g ) ; At 25 C If 1. Drag the appropriate items to their respective bins. Calculate K for 2HI (g)⇌H2 ( g)+I2 ( g) at this temperature. C. H2 (g)+I2 (g)⇌2HI (g) has Δ H =−2.75M and [I2]=2. Copy link. Balance the The oxidation state of an element in its elementary state, such as H₂ or I₂, is always 0.250 M 0.6 × 10−3 at 25∘C If 1. (Express your answer using two H2 (g) +I2 (g) <-----> 2HI (g) At equilibrium in a particular experiment, the concentrations of H2,I2 , and HI were 0. So, this is indeed a redox reaction because oxidation (the loss of electrons as seen in The equilibrium constant, Kc, for the following reaction is 1.94×10-2 at 728 K.52 x 10-7 L/mols. Reaction Information Word Equation Hydrogen Iodide = Dihydrogen + Diiodine Consider the gas-phase reaction H2 (g) + I2 (g) ⇄ 2 HI (g) Suppose that a sealed flask containing H2 and I2 has been heated to 425 °C and the initial concentrations of H2 and I2 were each 0.Moscow was one of the primary military and political It was the latest step in an ongoing crackdown on L.4x10^-2 atm, pI2=4. 1, 2023.2.6} \] Increasing the temperature of the reaction increases the internal energy of the system. So if you add heat, more N2 (g) and H2 (g) will be created and balance out the reaction.82 × 10-1. What concentration of HI is present at equilibrium? 2HI (g) -> H2 (g) + I2 (g) There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are 2 HI molecules on the left.00 mole of HI are introduced into a 1.290 at 400 K. Shown below is an incomplete energy diagram for the reaction. The equilibrium reaction can be written as follows: 2HI(g) ⇌ H2(g) + I2(g). The potential energy of the reactants is indicated on the diagram. Of 0. Answer: Increasing the temperature will cause the equilibrium to shift towards the reactants (left).20M.78 atm O 0. In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI. The equilibrium concentration of I2 is 0.25 Consider the reaction: H2 (g) +I2 (g) 2 HI (g) A reaction mixture in a 3.4 = t retfa IH fo noitartnecnoc eht eb lliw tahW .75 M I2, what is the equilibrium concentration of HI? The activation energy for the decomposition of Hi(g) to H2(g) and I2(g) is 186 kJ/mol. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.50 M? 613. Run in the reverse direction to restablish equilibrium.484 M , and [HI]=4.450 mol/L∙s.484 M , [I2]=0..3 HI(g) 25. The reaction.393 M.0552 mol of HI in a volume of 735 cm3 . Chemistry. About us.0% reacted at 731 K.020 H2 (g) + I2 (g) → 2HI (g) What is the free energy change, Δ G ° (kJ), for the equilibrium between Chemistry question on rate laws. 2HI(g)?H2(g)+I2(g) Here’s the best way to solve it.8. The equilibrium constant, Kc, for the following reaction is 1. 1. What is the rate of appearance of I2 over the same period? a.27 mol/L. (Please show me the step-by-step math needed to achieve this 2 H I (g) ⇌ H 2 (g) + I 2 (g), For the above reaction the degree of dissociation ( α ) of HI (g) is related to equilibrium constant K p by the expression : View Solution The concentrations of HI and I2 will increase as the system is approaching. where K K is the equilibrium constant expressed in units of concentration and Δn Δ n is the difference between the numbers of moles of gaseous products and gaseous reactants ( np −nr n p − n r ).00 mole of I2, and 1. Unlock. HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K.00 × 10^−19 at 298 K what can be said about this reaction at this temperature? The equilibrium lies far to the left.) Convert the values of Kc to values of K p or the values of K p to values of Kc. Solution.75M[H2]=3. The equilibrium constant for a system will be symbolized by the letter: K.200 M, and [HI] = 3. Equilibrium concentration of H1 increases 2.80×10-4 mol L-1 s-1 If the experiment has an initial HI concentration of 0.00414 mol of I2, and 0.390 mol/L, what is the concentration of HI after 28.s-1 : 2HI (g) → H2 (g) + I2 (g) 1) Based on the units of the rate constant, is the reaction first order or second order? Explain. Tổng nhiệt phá vỡ liên kết của chất phản ứng lớn hơn nhiệt tỏa ra khi tạo thành Question: Hydrogen iodide decomposes according to the equation 2HI(g) H2(g) + I2(g), for which Kc = 0., When the substances in the equation below are at equilibrium, at pressure P and temperature T, the equilibrium can be shifted to favor the The correct answer is 0. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a. The reaction is second order and has a rate constant equal to 1. 1 Answer Stefan V. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a. When the system comes to equilibrium at 400°C, what will be the total pressure inside the reaction vessel? 2HI (g) % H2 (g) + 12 (g), Kc = 0.638 0.6x10^-1 atm. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) ↔ H2(g) + I2(g)When the system comes to equilibrium at 425 °C, PHI = 0. What is the equilibrium constant for the reaction H2 (g)+I2 (g)⇌2HI (g) at 700 K? This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.0175 mol/L.15 M I2 at equilibrium.60 mol/L, [H2] = .2Group of answer choices0. Bin options: 1.0 (c) CO2 (𝑔)+H2 (𝑔) CO (𝑔)+H2O (𝑔) T=980°C 𝐾𝑝=1. Transcribed image text: 25. where K K is the equilibrium constant expressed in units of concentration and Δn Δ n is the difference … \[\ce{H2(g) + I2(g) \rightleftharpoons 2HI(g)} + \text{heat} \label{15.498 M I 2. Phát biểu nào sau đây về sự trao đổi năng lượng của phản ứng trên là đúng? A., As the reaction quotient Q increases, what is the effect on the Chemistry questions and answers. We reviewed their content and use your Final answer. With time, the concentrations of H2 and I2 decline, and the concentration of HI increases.3 = ]IH[ dna ,M 002. Consider the second-order reaction: 2HI (g)→H2 (g)+I2 (g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. A) 4 Fe (s) + 3 O2 (g) 2 Fe2O3 (s) B) H2 (g) + Cl2 (g) 2 HCl (g) C) 2HI (g) H2 (g) + I2 (g) D) 2 SO3 (g) 2 SO2 (g) + O2 (g) E) N2 (g) + 3 H2 (g) 2 NH3 (g), 43) Of the following equilibria, only _____ will shift to the left in H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3.00 L reaction vessel at 400ºC. Chemistry questions and answers.314 J/molK) (ln 1.708 atm, and PH2=P12=0. H2(g)+I2(g)=2HI, Finding out final concentration of H2, I2 an… Balanced Chemical Equation 2 HI → H 2 + I 2 ⬇ Scroll down to see reaction info and a step-by-step answer, or balance another equation.0411 0.0 x 10-4 M? Question: Calculate ΔG° for each of the following reactions from the equilibrium constant at the temperature given. Show transcribed image text. Chemistry.85 mol/L, [I2] = . Expert-verified. 2HI(g)?H2(g)+I2(g) Determine the reaction quotient expression for the reversible reaction below.414 M, L) = 0. H2(g) + I2(g) 2HI(g) Initial 0. Use data from Appendix C to calculate the equilibrium constant, K, and Δ G ∘ at 298 K for each of the following reactions.15 K are summarized in Table 4. B.75-L flask at a certain temperature initially contains 0. What is the equilibrium concentration of H2? 2)For the reaction: 2HBr (g) ↔ H2 (g) + Br2 (g) Initially a container contains 0. At the start of the reaction there are 0.200 M, and [HI] = 3. For the reaction 2HI (g) ⇌H2 (g)+I2 (g), Kc= 0.80×10-2 at 698 2HI(g) --> H2(g) + I2(g) Rate = -d[HI]/dt = k = 1.43×10-2 at 1110 K. Question: What is the free energy change, ΔG° (kJ), for the equilibrium between hydrogen iodide, hydrogen, and iodine at 453°C? Kc = 0. ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. 2HI(g) H2(g) I2(g) K for the reaction is 0. See Answer Chemistry Chemistry questions and answers Hydrogen iodide decomposes according to the equation 2HI (g) H2 (g) + I2 (g), for which Kc = 0. What is the equilibrium concentration of H2? Question: Hydrogen iodide decomposes according to the equation 2HI (g) H2 (g) + I2 (g), for which Kc = 0. The following reaction was performed in a sealed vessel at 723 ∘C : H2 (g)+I2 (g)⇌2HI (g) Initially, only H2 and I2 were present at concentrations of [H2]=3.484 M , and [HI]=4.87×10 −4 MM . 1.50-L container initially holds 0.60 mol/L, [H2] = 0. 0.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H.036.10 x 10^-5 L/mols at 600 K. Equilibrium concentration of H1 decreases 3. What is the standard free energy change, ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. 0..428 moles of H2, and 0.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.)The equilibrium constant, Kc, for the following reaction is 1. H2 (g) + I2 (g) ⇋2HI (g) is 794 at 25 °C. This is because the reaction is exothermic and releases heat.300 mol of I2 were placed in a 1.200 mol H2 and 0. … Kp = K(RT)Δn (15. The equilibrium constant, K c, for the reaction H 2 ( g) + I 2 ( g) ⇄ 2HI ( g) at 425°C is 54.70 M I₂, the what is the equilibrium concentration of HI? MULTIPLE CHOICE.033M, and 0.059 g H2 and 4. The equilibrium constant, Kc, for the following reaction is 1.00-L reaction The equilibrium constant for the gas phase reaction H2 (g) + I2 (g) 2HI (g) is Keq = 50 at 25 °C.26 atm pressure of HI is admitted to the container, and it is allowed to come to equilibrium again.215 M H2, and 0.138 M d. The equilibrium constant (Kc) for the reaction H2 (g) + I2 (g) <=> 2HI (g) is 54." Russian media reported that two unmanned The Battle of Moscow was a military campaign that consisted of two periods of strategically significant fighting on a 600 km (370 mi) sector of the Eastern Front during World War II, between September 1941 and January 1942.00 mol of HI(g) is introduced into the reaction vessel, what are 2HI(g)⇌H2(g)+I2(g) Select the correct answer below: Qc=[HI]2[H2][I2] Qc=[H2][I2][HI] Qc=[H2][I2][HI]2. Chemistry Chemistry questions and answers For the reaction 2HI (g)⇌H2 (g)+I2 (g), the equilibrium constant Kc=1.708 atm, and PH2 = PI2 = 0.9.87×10 −4 MM , and [I2]=[I2]= 4.30 kJ/mol at 25°C. Consider the following reaction: 2HI (g) H2 (g) + I2 (g) If 3.0200 M . Who are the experts? Experts have been vetted by Chegg as specialists in this subject. Suppose 0. Thanks! HI decomposes to H2 and I2 by the following equation: 2HI (g) → H2 (g) + I2 (g);Kc = 1.35 M0. 0.016 Initially a container contains 0. These results can be used to calculate the standard Gibbs free … verified answered • expert verified H 2 (g)+I 2 (g)→2 H I (g) ΔH∘r x n=−9. 2HI(g) = H2(g) + I2(g) Calculate Kc at this temperature for the following reaction: HI(g) =1/2H2(g) + 1/2I2(g) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. H2(g) + I2(g) ⇌ 2HI (g) = -9,6 kJ. Flashcards; Test; Learn Study with Quizlet and memorize flashcards containing terms like The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2HI (g) is 794 at 25 °C.40-L reaction chamber. Kc = 56.2 kcal/mol (−9. Shown below is an incomplete energy diagram for the reaction.6 x 10-3 L mol-1 s-1 at 700 °C.5 k J/m o l r x n H 2 (g) and I 2 (g) can react to produce HI (g) , as represented above. a) H2 ( g )+I2 ( g )⇌2HI ( g) Calculate Δ G ∘.45 M HI and no product. (Express your answer to four significant figures and include the appropriate units.Q.2. What is the activation energy of this reaction? Question: Given a reversible chemical reaction: H2(g) + I2(g) ⇌ 2HI(g) Kc = 64. + 2 H2(g) ⇌ CH3OH (g)In an experiment, 0.100 mol I2 were placed in a 1.0275 M c. See Answer Balanced Chemical Equation 2 HI → H 2 + I 2 ⬇ Scroll down to see reaction info and a step-by-step answer, or balance another equation.122 at For the reaction 2HBr(g) ⇌ H2(g) + Br2(g) K = 2.